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翻訳と辞書　辞書検索 [ 開発暫定版 ] スポンサード リンク product measure ： ウィキペディア英語版 product measure In mathematics, given two measurable spaces and measures on them, one can obtain a product measurable space and a product measure on that space. Conceptually, this is similar to defining the Cartesian product of sets and the product topology of two topological spaces, except that there can be many natural choices for the product measure. Let $(X\_1,\; \backslash Sigma\_1)$ and $(X\_2,\; \backslash Sigma\_2)$ be two measurable spaces, that is, $\backslash Sigma\_1$ and $\backslash Sigma\_2$ are sigma algebras on $X\_1$ and $X\_2$ respectively, and let $\backslash mu\_1$ and $\backslash mu\_2$ be measures on these spaces. Denote by $\backslash Sigma\_1\; \backslash otimes\; \backslash Sigma\_2$ the sigma algebra on the Cartesian product $X\_1\; \backslash times\; X\_2$ generated by subsets of the form $B\_1\; \backslash times\; B\_2$, where $B\_1\; \backslash in\; \backslash Sigma\_1$ and $B\_2\; \backslash in\; \backslash Sigma\_2.$ This sigma algebra is called the ''tensor-product σ-algebra'' on the product space. A ''product measure'' $\backslash mu\_1\; \backslash times\; \backslash mu\_2$ is defined to be a measure on the measurable space $(X\_1\; \backslash times\; X\_2,\; \backslash Sigma\_1\; \backslash otimes\; \backslash Sigma\_2)$ satisfying the property :$(\backslash mu\_1\; \backslash times\; \backslash mu\_2)(B\_1\; \backslash times\; B\_2)\; =\; \backslash mu\_1(B\_1)\; \backslash mu\_2(B\_2)$ for all :$B\_1\; \backslash in\; \backslash Sigma\_1,\backslash \; B\_2\; \backslash in\; \backslash Sigma\_2$. (In multiplying measures, some of which are infinite, we define the product to be zero if any factor is zero.) In fact, when the spaces are $\backslash sigma$-finite, the product measure is uniquely defined, and for every measurable set ''E'', :$(\backslash mu\_1\; \backslash times\; \backslash mu\_2)(E)\; =\; \backslash int\_\; \backslash mu\_1(E^y)\backslash ,d\backslash mu\_2(y)\; =\; \backslash int\_\; \backslash mu\_2(E\_)\backslash ,d\backslash mu\_1(x),$ where $E\_x\; =\; \backslash$ and $E^y\; =\; \backslash$, which are both measurable sets. The existence of this measure is guaranteed by the Hahn–Kolmogorov theorem. The uniqueness of product measure is guaranteed only in the case that both $(X\_1,\; \backslash Sigma\_1,\; \backslash mu\_1)$ and $(X\_2,\; \backslash Sigma\_2,\; \backslash mu\_2)$ are σ-finite. The Borel measure on the Euclidean space R''n'' can be obtained as the product of ''n'' copies of the Borel measure on the real line R. Even if the two factors of the product space are complete measure spaces, the product space may not be. Consequently, the completion procedure is needed to extend the Borel measure into the Lebesgue measure, or to extend the product of two Lebesgue measures to give the Lebesgue measure on the product space. The opposite construction to the formation of the product of two measures is disintegration, which in some sense "splits" a given measure into a family of measures that can be integrated to give the original measure. ==Examples== *Given two measure spaces, there is always a unique maximal product measure μmax on their product, with the property that if μmax(''A'') is finite for some measurable set ''A'', then μmax(''A'') = μ(''A'') for any product measure μ. In particular its value on any measurable set is at least that of any other product measure. This is the measure produced by the Carathéodory extension theorem. *There is always a unique minimal product measure μmin, given by μmin(''S'') = sup''A''⊂''S'', μmax(''A'') finite μmax(''A''), where ''A'' and ''S'' are assumed to be measurable. *Here is an example where a product has more than one product measure. Take the product ''X''×''Y'', where ''X'' is the unit interval with Lebesgue measure, and ''Y'' is the unit interval with counting measure and all sets measurable. Then for the minimal product measure the measure of a set is the sum of the measures of its horizontal sections, while for the maximal product measure a set has measure infinity unless it is contained in the union of a countable number of sets of the form ''A''×''B'', where either ''A'' has Lebesgue measure 0 or ''B'' is a single point. (In this case the measure may be finite or infinite.) In particular, the diagonal has measure 0 for the minimal product measure and measure infinity for the maximal product measure. 抄文引用元・出典: フリー百科事典『 ウィキペディア（Wikipedia）』 ■ウィキペディアで「product measure」の詳細全文を読む スポンサード リンク 翻訳と辞書 : 翻訳のためのインターネットリソース Copyright(C) kotoba.ne.jp 1997-2016. All Rights Reserved.